Duvelthehobbit666
New Member
I have a question. Is the equation for the average sherwood number for a cylinder parallel to a flow outside the cylinder 0.664*(Re^0.5)*Sc^(1/3)?
Thanks in advanced.
Thanks in advanced.
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Sherwood question
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RichardMNixon
New Member
It might depend on what your Re is.
Bird, Stewart, and Lightfoot has this for the Nusselt number, but I think it should be directly analogous. It's only for Re < 10^5 though.
Sh = [0.4*Re^0.5 + 0.06*Re^(2/3)] Sc^0.4 [viscosity(bulk)/viscosity(surface)]^0.25
I imagine the viscosity ratio could probably be ignored if you didn't have a temperature gradient at which point it would look very similar to yours.
If I remember when I get home I can check my notes for any other formulations.
Bird, Stewart, and Lightfoot has this for the Nusselt number, but I think it should be directly analogous. It's only for Re < 10^5 though.
Sh = [0.4*Re^0.5 + 0.06*Re^(2/3)] Sc^0.4 [viscosity(bulk)/viscosity(surface)]^0.25
I imagine the viscosity ratio could probably be ignored if you didn't have a temperature gradient at which point it would look very similar to yours.
If I remember when I get home I can check my notes for any other formulations.
Duvelthehobbit666
New Member
I already found it. It was for a turbulent flow and it is 0.0292Re^0.8*Sc^(1/3)
thanks for your help though.
Lock thread please?
thanks for your help though.
Lock thread please?
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